How Much Force Can I Get Out of a 2 Inch Hydraulic Cylinder
The force produced on the rod side(1) of a double acting hydraulic piston - can be expressed as
F1 = P1 (π (d2 2 - done 2) / four) (1)
where
F1 = rod strength (lb, N)
dane = rod bore (in, mm)
d2 = piston diameter (in, mm)
Pi = pressure level in the cylinder on the rod side (psi, North/mm2)
- 1 bar = 105 North/mii = 0.1 Nm/mmtwo
The force produced on the reverse of rod side (2) - can be expressed as
F2 = P2 (π dtwo ii / iv) (2)
where
F2 = rod force (lb, N)
Pii = pressure in the cylinder (opposite rod) ( psi, N/mm2 )
Hydraulic Force Reckoner
Majestic Units
Pressure acting on rod side
Pressure acting on contrary of rod side
Piston diameter - d2 (in)
Cylinder force per unit area - d2 (psi)
Metric Units
Pressure acting on rod side
Piston bore - d2 (mm)
Rod diameter - d1 (mm)
Cylinder pressure - Pi (bar)
Pressure acting on opposite of rod side
Piston bore - d2 (mm)
Cylinder pressure - d2 (bar )
Related Mobile Apps from The Engineering ToolBox
- Hydraulic Forcefulness Calculator App
- free apps for offline use on mobile devices.
Rod Strength F2 diagram
- when force per unit area act on opposite side of rod.
Regal Units
Metric Units
- ane psi (lb/in2) = 144 psf (lbf/ft2) = 6,894.8 Pa (Due north/m2) = 6.895x10-three Northward/mmtwo = six.895x10-2 bar
- 1 N/g2 = 1 Pa = 1.4504x10-4 lb/in2 = 1x10-5 bar = iv.03x10-iii in water = 0.336x10-3 ft water = 0.1024 mm water = 0.295x10-3 in mercury = 7.55x10-iii mm mercury = 0.1024 kg/m2 = 0.993x10-5 atm
- 1 lbf (Pound force) = 4.44822 Due north = 0.4536 kp
- 1 N (Newton) = 0.1020 kp = vii.233 pdl = seven.233/32.174 lbf = 0.2248 lbf = 1 (kg thousand)/s2 = xfive dyne = 1/9.80665 kgf
- 1 in (inch) = 25.4 mm
- 1 m (meter) = 39.37 in = 100 cm = 1000 mm
Rod Force Fane diagram
- when force per unit area act on the same side of the rod.
Imperial Units
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Source: https://www.engineeringtoolbox.com/hydraulic-force-calculator-d_1369.html
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